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1315230047 is a prime number
BaseRepresentation
bin100111001100100…
…1101000101011111
310101122211121102222
41032121031011133
510143144330142
6334301535555
744410161635
oct11631150537
93348747388
101315230047
1161545a88a
123085745bb
1317c63b241
14c6967355
157a6ecbd2
hex4e64d15f

1315230047 has 2 divisors, whose sum is σ = 1315230048. Its totient is φ = 1315230046.

The previous prime is 1315230019. The next prime is 1315230053. The reversal of 1315230047 is 7400325131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1315230047 - 28 = 1315229791 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1315229998 and 1315230025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315230247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657615023 + 657615024.

It is an arithmetic number, because the mean of its divisors is an integer number (657615024).

Almost surely, 21315230047 is an apocalyptic number.

1315230047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315230047 is an equidigital number, since it uses as much as digits as its factorization.

1315230047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 1315230047 is about 36266.1005210100. The cubic root of 1315230047 is about 1095.6383889603.

Adding to 1315230047 its reverse (7400325131), we get a palindrome (8715555178).

The spelling of 1315230047 in words is "one billion, three hundred fifteen million, two hundred thirty thousand, forty-seven".