Base | Representation |
---|---|
bin | 10011001000111011101… |
… | …001111101101111111111 |
3 | 11122201220210022220200101 |
4 | 103020323221331233333 |
5 | 133022123234133101 |
6 | 2444120020341531 |
7 | 164011250520064 |
oct | 23107351755777 |
9 | 4581823286611 |
10 | 1315260849151 |
11 | 467887508017 |
12 | 192aa62448a7 |
13 | 9704a9b40b2 |
14 | 479322b0c6b |
15 | 2432dab3401 |
hex | 1323ba7dbff |
1315260849151 has 2 divisors, whose sum is σ = 1315260849152. Its totient is φ = 1315260849150.
The previous prime is 1315260849127. The next prime is 1315260849163. The reversal of 1315260849151 is 1519480625131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1315260849151 - 219 = 1315260324863 is a prime.
It is a super-2 number, since 2×13152608491512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1315260844151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657630424575 + 657630424576.
It is an arithmetic number, because the mean of its divisors is an integer number (657630424576).
Almost surely, 21315260849151 is an apocalyptic number.
1315260849151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315260849151 is an equidigital number, since it uses as much as digits as its factorization.
1315260849151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 46.
The spelling of 1315260849151 in words is "one trillion, three hundred fifteen billion, two hundred sixty million, eight hundred forty-nine thousand, one hundred fifty-one".
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