Base | Representation |
---|---|
bin | 1011111101100110111010… |
… | …0001000111011000111011 |
3 | 1201120102022020212001022221 |
4 | 2333121232201013120323 |
5 | 3210444413233111011 |
6 | 43550231445224511 |
7 | 2525163456420550 |
oct | 277315641073073 |
9 | 51512266761287 |
10 | 13153044035131 |
11 | 42111a1505560 |
12 | 1585193a02137 |
13 | 745432a994a0 |
14 | 336879ba2a27 |
15 | 17c21a607971 |
hex | bf66e84763b |
13153044035131 has 32 divisors (see below), whose sum is σ = 17748775296000. Its totient is φ = 9413189470080.
The previous prime is 13153044035111. The next prime is 13153044035141.
13153044035131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13153044035131 - 29 = 13153044034619 is a prime.
It is a super-2 number, since 2×131530440351312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13153044035111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32815636 + ... + 33214033.
It is an arithmetic number, because the mean of its divisors is an integer number (554649228000).
Almost surely, 213153044035131 is an apocalyptic number.
13153044035131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13153044035131 is a deficient number, since it is larger than the sum of its proper divisors (4595731260869).
13153044035131 is a wasteful number, since it uses less digits than its factorization.
13153044035131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66029899.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 13153044035131 in words is "thirteen trillion, one hundred fifty-three billion, forty-four million, thirty-five thousand, one hundred thirty-one".
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