Base | Representation |
---|---|
bin | 10011001000111110010… |
… | …010100011010000100011 |
3 | 11122202000212111012012211 |
4 | 103020332102203100203 |
5 | 133022221042333404 |
6 | 2444124235502551 |
7 | 164012325253054 |
oct | 23107622432043 |
9 | 4582025435184 |
10 | 1315305042979 |
11 | 4678aa452544 |
12 | 192ab8bb7a57 |
13 | 97056bb87a5 |
14 | 479380d672b |
15 | 243328e2b04 |
hex | 1323e4a3423 |
1315305042979 has 2 divisors, whose sum is σ = 1315305042980. Its totient is φ = 1315305042978.
The previous prime is 1315305042929. The next prime is 1315305043001. The reversal of 1315305042979 is 9792405035131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1315305042979 - 213 = 1315305034787 is a prime.
It is not a weakly prime, because it can be changed into another prime (1315305042929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657652521489 + 657652521490.
It is an arithmetic number, because the mean of its divisors is an integer number (657652521490).
Almost surely, 21315305042979 is an apocalyptic number.
1315305042979 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315305042979 is an equidigital number, since it uses as much as digits as its factorization.
1315305042979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1020600, while the sum is 49.
The spelling of 1315305042979 in words is "one trillion, three hundred fifteen billion, three hundred five million, forty-two thousand, nine hundred seventy-nine".
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