Base | Representation |
---|---|
bin | 11101111010000010000110… |
… | …000000000000001010010011 |
3 | 122020201021100022012121210221 |
4 | 131322002012000000022103 |
5 | 114220002124103322212 |
6 | 1143424353545533511 |
7 | 36463552614210535 |
oct | 3572020600001223 |
9 | 566637308177727 |
10 | 131531326620307 |
11 | 38a01138954069 |
12 | 1290379b1a4297 |
13 | 5851473b5c3c3 |
14 | 246a216123855 |
15 | 1031671c69807 |
hex | 77a086000293 |
131531326620307 has 2 divisors, whose sum is σ = 131531326620308. Its totient is φ = 131531326620306.
The previous prime is 131531326620293. The next prime is 131531326620319. The reversal of 131531326620307 is 703026623135131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131531326620307 is a prime.
It is not a weakly prime, because it can be changed into another prime (131531326620367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65765663310153 + 65765663310154.
It is an arithmetic number, because the mean of its divisors is an integer number (65765663310154).
Almost surely, 2131531326620307 is an apocalyptic number.
131531326620307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131531326620307 is an equidigital number, since it uses as much as digits as its factorization.
131531326620307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
Adding to 131531326620307 its reverse (703026623135131), we get a palindrome (834557949755438).
The spelling of 131531326620307 in words is "one hundred thirty-one trillion, five hundred thirty-one billion, three hundred twenty-six million, six hundred twenty thousand, three hundred seven".
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