Base | Representation |
---|---|
bin | 11101111010000011110110… |
… | …011010001100001100000000 |
3 | 122020201110012201212221100212 |
4 | 131322003312122030030000 |
5 | 114220020004402033004 |
6 | 1143425305035333252 |
7 | 36463650424206665 |
oct | 3572036632141400 |
9 | 566643181787325 |
10 | 131533212533504 |
11 | 38a01a16458611 |
12 | 129040268b1228 |
13 | 58516b47a0182 |
14 | 246a3547a1a6c |
15 | 10317325e396e |
hex | 77a0f668c300 |
131533212533504 has 18 divisors (see below), whose sum is σ = 262552623456060. Its totient is φ = 65766606266624.
The previous prime is 131533212533501. The next prime is 131533212533509. The reversal of 131533212533504 is 405335212335131.
It is not an unprimeable number, because it can be changed into a prime (131533212533501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256900805474 + ... + 256900805985.
It is an arithmetic number, because the mean of its divisors is an integer number (14586256858670).
Almost surely, 2131533212533504 is an apocalyptic number.
It is an amenable number.
131533212533504 is a deficient number, since it is larger than the sum of its proper divisors (131019410922556).
131533212533504 is an frugal number, since it uses more digits than its factorization.
131533212533504 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 513801611475 (or 513801611461 counting only the distinct ones).
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 131533212533504 its reverse (405335212335131), we get a palindrome (536868424868635).
The spelling of 131533212533504 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, two hundred twelve million, five hundred thirty-three thousand, five hundred four".
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