Base | Representation |
---|---|
bin | 11101111010000100000001… |
… | …101001010001001100011111 |
3 | 122020201110200212120211120011 |
4 | 131322010001221101030133 |
5 | 114220020401131114201 |
6 | 1143425335451504051 |
7 | 36463655203355434 |
oct | 3572040151211437 |
9 | 566643625524504 |
10 | 131533401035551 |
11 | 38a020028a7a29 |
12 | 12904079a58027 |
13 | 585171485cb48 |
14 | 246a37182db8b |
15 | 1031743e2b151 |
hex | 77a101a5131f |
131533401035551 has 2 divisors, whose sum is σ = 131533401035552. Its totient is φ = 131533401035550.
The previous prime is 131533401035539. The next prime is 131533401035557. The reversal of 131533401035551 is 155530104335131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131533401035551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131533401035557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65766700517775 + 65766700517776.
It is an arithmetic number, because the mean of its divisors is an integer number (65766700517776).
Almost surely, 2131533401035551 is an apocalyptic number.
131533401035551 is a deficient number, since it is larger than the sum of its proper divisors (1).
131533401035551 is an equidigital number, since it uses as much as digits as its factorization.
131533401035551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 202500, while the sum is 40.
The spelling of 131533401035551 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, four hundred one million, thirty-five thousand, five hundred fifty-one".
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