1315343450219 has 2 divisors, whose sum is σ = 1315343450220. Its totient is φ = 1315343450218.

The previous prime is 1315343450129. The next prime is 1315343450221. The reversal of 1315343450219 is 9120543435131.

Together with previous prime (1315343450129) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1315343450219 is a prime.

It is a super-2 number, since 2×1315343450219² (a number of 25 digits) contains 22 as substring.

Together with 1315343450221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1315343450819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657671725109 + 657671725110.

It is an arithmetic number, because the mean of its divisors is an integer number (657671725110).

Almost surely, 2^{1315343450219} is an apocalyptic number.

1315343450219 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315343450219 is an equidigital number, since it uses as much as digits as its factorization.

1315343450219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 41.

The spelling of 1315343450219 in words is "one trillion, three hundred fifteen billion, three hundred forty-three million, four hundred fifty thousand, two hundred nineteen".