Base | Representation |
---|---|
bin | 111101010000001101… |
… | …0001111001011001101 |
3 | 110120112021012010020210 |
4 | 1322200122033023031 |
5 | 4123343301020331 |
6 | 140232340033033 |
7 | 12334455455022 |
oct | 1724032171315 |
9 | 416467163223 |
10 | 131540251341 |
11 | 50871051824 |
12 | 215b0692779 |
13 | c53401ab65 |
14 | 651bc89549 |
15 | 364d1ae446 |
hex | 1ea068f2cd |
131540251341 has 16 divisors (see below), whose sum is σ = 176573053440. Its totient is φ = 87101146800.
The previous prime is 131540251321. The next prime is 131540251363. The reversal of 131540251341 is 143152045131.
It is not a de Polignac number, because 131540251341 - 25 = 131540251309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131540251299 and 131540251308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131540251321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 708616 + ... + 874766.
It is an arithmetic number, because the mean of its divisors is an integer number (11035815840).
Almost surely, 2131540251341 is an apocalyptic number.
It is an amenable number.
131540251341 is a deficient number, since it is larger than the sum of its proper divisors (45032802099).
131540251341 is a wasteful number, since it uses less digits than its factorization.
131540251341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167936.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 131540251341 its reverse (143152045131), we get a palindrome (274692296472).
The spelling of 131540251341 in words is "one hundred thirty-one billion, five hundred forty million, two hundred fifty-one thousand, three hundred forty-one".
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