Base | Representation |
---|---|
bin | 10011001001000101001… |
… | …101010111100110001000 |
3 | 11122202022221220202210221 |
4 | 103021011031113212020 |
5 | 133022440302000000 |
6 | 2444143543515424 |
7 | 164015235035443 |
oct | 23110515274610 |
9 | 4582287822727 |
10 | 1315421125000 |
11 | 467959a286a4 |
12 | 192b2ba58b74 |
13 | 97074c70288 |
14 | 479496b265a |
15 | 2433cbc261a |
hex | 13245357988 |
1315421125000 has 56 divisors (see below), whose sum is σ = 3082979092050. Its totient is φ = 526168400000.
The previous prime is 1315421124967. The next prime is 1315421125013. The reversal of 1315421125000 is 5211245131.
It can be written as a sum of positive squares in 7 ways, for example, as 1111350290436 + 204070834564 = 1054206^2 + 451742^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 5136685 + ... + 5386684.
Almost surely, 21315421125000 is an apocalyptic number.
1315421125000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1315421125000 is an abundant number, since it is smaller than the sum of its proper divisors (1767557967050).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1315421125000 is an frugal number, since it uses more digits than its factorization.
1315421125000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10523405 (or 10523376 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
The spelling of 1315421125000 in words is "one trillion, three hundred fifteen billion, four hundred twenty-one million, one hundred twenty-five thousand".
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