Base | Representation |
---|---|
bin | 1011111101101011101000… |
… | …1110011101001001010011 |
3 | 1201120112120202220201022211 |
4 | 2333122322032131021103 |
5 | 3211010013414240143 |
6 | 43551001501412551 |
7 | 2525240111640103 |
oct | 277327216351123 |
9 | 51515522821284 |
10 | 13154314211923 |
11 | 4211793493145 |
12 | 158548926a157 |
13 | 7455a5c91aa1 |
14 | 33695a75d203 |
15 | 17c291da649d |
hex | bf6ba39d253 |
13154314211923 has 2 divisors, whose sum is σ = 13154314211924. Its totient is φ = 13154314211922.
The previous prime is 13154314211921. The next prime is 13154314211947. The reversal of 13154314211923 is 32911241345131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13154314211923 - 21 = 13154314211921 is a prime.
Together with 13154314211921, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13154314211921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577157105961 + 6577157105962.
It is an arithmetic number, because the mean of its divisors is an integer number (6577157105962).
Almost surely, 213154314211923 is an apocalyptic number.
13154314211923 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154314211923 is an equidigital number, since it uses as much as digits as its factorization.
13154314211923 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 40.
The spelling of 13154314211923 in words is "thirteen trillion, one hundred fifty-four billion, three hundred fourteen million, two hundred eleven thousand, nine hundred twenty-three".
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