Base | Representation |
---|---|
bin | 1011111101101011110010… |
… | …0100011010110110011111 |
3 | 1201120112200111212222112101 |
4 | 2333122330210122312133 |
5 | 3211010104000233002 |
6 | 43551005424145531 |
7 | 2525241100041664 |
oct | 277327444326637 |
9 | 51515614788471 |
10 | 13154353524127 |
11 | 42118036a3a72 |
12 | 158549a4682a7 |
13 | 7455b117754a |
14 | 336961a73a6b |
15 | 17c29556e587 |
hex | bf6bc91ad9f |
13154353524127 has 2 divisors, whose sum is σ = 13154353524128. Its totient is φ = 13154353524126.
The previous prime is 13154353524077. The next prime is 13154353524149. The reversal of 13154353524127 is 72142535345131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13154353524127 is a prime.
It is a super-2 number, since 2×131543535241272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13154353524167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577176762063 + 6577176762064.
It is an arithmetic number, because the mean of its divisors is an integer number (6577176762064).
Almost surely, 213154353524127 is an apocalyptic number.
13154353524127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154353524127 is an equidigital number, since it uses as much as digits as its factorization.
13154353524127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1512000, while the sum is 46.
Adding to 13154353524127 its reverse (72142535345131), we get a palindrome (85296888869258).
The spelling of 13154353524127 in words is "thirteen trillion, one hundred fifty-four billion, three hundred fifty-three million, five hundred twenty-four thousand, one hundred twenty-seven".
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