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13154404314193 is a prime number
BaseRepresentation
bin1011111101101011111110…
…0110001010110001010001
31201120112211001110101101221
42333122333212022301101
53211010210001023233
643551014440525041
72525242254536662
oct277327746126121
951515731411357
1013154404314193
11421182a33432a
1215854b3480781
137455bb84b43c
143369686d5369
1517c299c5342d
hexbf6bf98ac51

13154404314193 has 2 divisors, whose sum is σ = 13154404314194. Its totient is φ = 13154404314192.

The previous prime is 13154404314113. The next prime is 13154404314253. The reversal of 13154404314193 is 39141340445131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12707635059729 + 446769254464 = 3564777^2 + 668408^2 .

It is a cyclic number.

It is not a de Polignac number, because 13154404314193 - 221 = 13154402217041 is a prime.

It is a super-2 number, since 2×131544043141932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13154404314113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577202157096 + 6577202157097.

It is an arithmetic number, because the mean of its divisors is an integer number (6577202157097).

Almost surely, 213154404314193 is an apocalyptic number.

It is an amenable number.

13154404314193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154404314193 is an equidigital number, since it uses as much as digits as its factorization.

13154404314193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 13154404314193 in words is "thirteen trillion, one hundred fifty-four billion, four hundred four million, three hundred fourteen thousand, one hundred ninety-three".