Base | Representation |
---|---|
bin | 1011111101101011111110… |
… | …0110001010110010001101 |
3 | 1201120112211001110101111011 |
4 | 2333122333212022302031 |
5 | 3211010210001024003 |
6 | 43551014440525221 |
7 | 2525242254540106 |
oct | 277327746126215 |
9 | 51515731411434 |
10 | 13154404314253 |
11 | 421182a334384 |
12 | 15854b3480811 |
13 | 7455bb84b487 |
14 | 3369686d53ad |
15 | 17c299c5346d |
hex | bf6bf98ac8d |
13154404314253 has 2 divisors, whose sum is σ = 13154404314254. Its totient is φ = 13154404314252.
The previous prime is 13154404314193. The next prime is 13154404314263. The reversal of 13154404314253 is 35241340445131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9437540355364 + 3716863958889 = 3072058^2 + 1927917^2 .
It is a cyclic number.
It is not a de Polignac number, because 13154404314253 - 225 = 13154370759821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13154404314263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577202157126 + 6577202157127.
It is an arithmetic number, because the mean of its divisors is an integer number (6577202157127).
Almost surely, 213154404314253 is an apocalyptic number.
It is an amenable number.
13154404314253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154404314253 is an equidigital number, since it uses as much as digits as its factorization.
13154404314253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 13154404314253 its reverse (35241340445131), we get a palindrome (48395744759384).
The spelling of 13154404314253 in words is "thirteen trillion, one hundred fifty-four billion, four hundred four million, three hundred fourteen thousand, two hundred fifty-three".
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