Base | Representation |
---|---|
bin | 1011111101101110110000… |
… | …0100101010011000111011 |
3 | 1201120121202001112211111011 |
4 | 2333123230010222120323 |
5 | 3211013222012134111 |
6 | 43551220454214351 |
7 | 2525266615213636 |
oct | 277335404523073 |
9 | 51517661484434 |
10 | 13155150505531 |
11 | 4212082562991 |
12 | 15856813543b7 |
13 | 7456aa311488 |
14 | 3369d9854c1d |
15 | 17c2e04ec021 |
hex | bf6ec12a63b |
13155150505531 has 2 divisors, whose sum is σ = 13155150505532. Its totient is φ = 13155150505530.
The previous prime is 13155150505517. The next prime is 13155150505571. The reversal of 13155150505531 is 13550505155131.
It is an a-pointer prime, because the next prime (13155150505571) can be obtained adding 13155150505531 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13155150505531 - 25 = 13155150505499 is a prime.
It is a super-4 number, since 4×131551505055314 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13155150505571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577575252765 + 6577575252766.
It is an arithmetic number, because the mean of its divisors is an integer number (6577575252766).
Almost surely, 213155150505531 is an apocalyptic number.
13155150505531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155150505531 is an equidigital number, since it uses as much as digits as its factorization.
13155150505531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 140625, while the sum is 40.
The spelling of 13155150505531 in words is "thirteen trillion, one hundred fifty-five billion, one hundred fifty million, five hundred five thousand, five hundred thirty-one".
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