Base | Representation |
---|---|
bin | 11000100000001110… |
… | …00101111111100111 |
3 | 1020221210211020120221 |
4 | 30100013011333213 |
5 | 203420212300103 |
6 | 10013213305211 |
7 | 643666220512 |
oct | 142007057747 |
9 | 36853736527 |
10 | 13155196903 |
11 | 5640847162 |
12 | 2671795207 |
13 | 13185a01a4 |
14 | 8cb207d79 |
15 | 51edab1bd |
hex | 3101c5fe7 |
13155196903 has 2 divisors, whose sum is σ = 13155196904. Its totient is φ = 13155196902.
The previous prime is 13155196897. The next prime is 13155196927. The reversal of 13155196903 is 30969155131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13155196903 - 25 = 13155196871 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13155196903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13155196933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577598451 + 6577598452.
It is an arithmetic number, because the mean of its divisors is an integer number (6577598452).
Almost surely, 213155196903 is an apocalyptic number.
13155196903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155196903 is an equidigital number, since it uses as much as digits as its factorization.
13155196903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109350, while the sum is 43.
The spelling of 13155196903 in words is "thirteen billion, one hundred fifty-five million, one hundred ninety-six thousand, nine hundred three".
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