13155262433 has 2 divisors, whose sum is σ = 13155262434. Its totient is φ = 13155262432.

The previous prime is 13155262327. The next prime is 13155262441. The reversal of 13155262433 is 33426255131.

It is a happy number.

13155262433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11691664384 + 1463598049 = 108128^2 + 38257^2 .

It is an emirp because it is prime and its reverse (33426255131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13155262433 - 2¹⁶ = 13155196897 is a prime.

It is a super-2 number, since 2×13155262433² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13155262393 and 13155262402.

It is not a weakly prime, because it can be changed into another prime (13155262493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577631216 + 6577631217.

It is an arithmetic number, because the mean of its divisors is an integer number (6577631217).

Almost surely, 2^13155262433 is an apocalyptic number.

It is an amenable number.

13155262433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155262433 is an equidigital number, since it uses as much as digits as its factorization.

13155262433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 35.

The spelling of 13155262433 in words is "thirteen billion, one hundred fifty-five million, two hundred sixty-two thousand, four hundred thirty-three".