13155312511541 has 4 divisors (see below), whose sum is σ = 13435212777792. Its totient is φ = 12875412245292.

The previous prime is 13155312511507. The next prime is 13155312511547. The reversal of 13155312511541 is 14511521355131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13155312511541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13155312511495 and 13155312511504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13155312511547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139950133055 + ... + 139950133148.

It is an arithmetic number, because the mean of its divisors is an integer number (3358803194448).

Almost surely, 2^{13155312511541} is an apocalyptic number.

It is an amenable number.

13155312511541 is a deficient number, since it is larger than the sum of its proper divisors (279900266251).

13155312511541 is an equidigital number, since it uses as much as digits as its factorization.

13155312511541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279900266250.

The product of its digits is 45000, while the sum is 38.

Adding to 13155312511541 its reverse (14511521355131), we get a palindrome (27666833866672).

The spelling of 13155312511541 in words is "thirteen trillion, one hundred fifty-five billion, three hundred twelve million, five hundred eleven thousand, five hundred forty-one".