Base | Representation |
---|---|
bin | 1011111101101111101100… |
… | …0000001111000011100011 |
3 | 1201120122101111220102201220 |
4 | 2333123323000033003203 |
5 | 3211014230124100420 |
6 | 43551301403230123 |
7 | 2525306046340641 |
oct | 277337300170343 |
9 | 51518344812656 |
10 | 13155401003235 |
11 | 42121a09a6587 |
12 | 1585731218343 |
13 | 74571a19957a |
14 | 336a20c20191 |
15 | 17c3074cd840 |
hex | bf6fb00f0e3 |
13155401003235 has 64 divisors (see below), whose sum is σ = 22042256689152. Its totient is φ = 6694702350336.
The previous prime is 13155401003201. The next prime is 13155401003309. The reversal of 13155401003235 is 53230010455131.
It is not a de Polignac number, because 13155401003235 - 213 = 13155400995043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13155401003196 and 13155401003205.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3146179 + ... + 6017411.
It is an arithmetic number, because the mean of its divisors is an integer number (344410260768).
Almost surely, 213155401003235 is an apocalyptic number.
13155401003235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13155401003235 is a deficient number, since it is larger than the sum of its proper divisors (8886855685917).
13155401003235 is a wasteful number, since it uses less digits than its factorization.
13155401003235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2871452.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 13155401003235 its reverse (53230010455131), we get a palindrome (66385411458366).
The spelling of 13155401003235 in words is "thirteen trillion, one hundred fifty-five billion, four hundred one million, three thousand, two hundred thirty-five".
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