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1315540117 is a prime number
BaseRepresentation
bin100111001101001…
…1000110010010101
310101200102100210001
41032122120302111
510143234240432
6334312331301
744412622633
oct11632306225
93350370701
101315540117
11615651841
123086a3b31
1317c719408
14c6a08353
157a75e9e7
hex4e698c95

1315540117 has 2 divisors, whose sum is σ = 1315540118. Its totient is φ = 1315540116.

The previous prime is 1315540073. The next prime is 1315540133. The reversal of 1315540117 is 7110455131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 735982641 + 579557476 = 27129^2 + 24074^2 .

It is a cyclic number.

It is not a de Polignac number, because 1315540117 - 223 = 1307151509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315540517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657770058 + 657770059.

It is an arithmetic number, because the mean of its divisors is an integer number (657770059).

Almost surely, 21315540117 is an apocalyptic number.

It is an amenable number.

1315540117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315540117 is an equidigital number, since it uses as much as digits as its factorization.

1315540117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100, while the sum is 28.

The square root of 1315540117 is about 36270.3751979491. The cubic root of 1315540117 is about 1095.7244823659.

Adding to 1315540117 its reverse (7110455131), we get a palindrome (8425995248).

The spelling of 1315540117 in words is "one billion, three hundred fifteen million, five hundred forty thousand, one hundred seventeen".