Base | Representation |
---|---|
bin | 1011111101110000001100… |
… | …0000101100001100010000 |
3 | 1201120122201212200110112220 |
4 | 2333130003000230030100 |
5 | 3211020014021342204 |
6 | 43551323002421040 |
7 | 2525312300234130 |
oct | 277340300541420 |
9 | 51518655613486 |
10 | 13155535340304 |
11 | 421225a80aa55 |
12 | 158576a201780 |
13 | 74573bc73166 |
14 | 336a349ccac0 |
15 | 17c3141b71d9 |
hex | bf70302c310 |
13155535340304 has 80 divisors (see below), whose sum is σ = 38841224443008. Its totient is φ = 3758620594176.
The previous prime is 13155535340249. The next prime is 13155535340333. The reversal of 13155535340304 is 40304353555131.
It is a super-2 number, since 2×131555353403042 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12083904 + ... + 13127520.
Almost surely, 213155535340304 is an apocalyptic number.
13155535340304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13155535340304 is an abundant number, since it is smaller than the sum of its proper divisors (25685689102704).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13155535340304 is a wasteful number, since it uses less digits than its factorization.
13155535340304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1081152 (or 1081146 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 42.
Adding to 13155535340304 its reverse (40304353555131), we get a palindrome (53459888895435).
The spelling of 13155535340304 in words is "thirteen trillion, one hundred fifty-five billion, five hundred thirty-five million, three hundred forty thousand, three hundred four".
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