131574113440 has 384 divisors, whose sum is σ = 410903248896. Its totient is φ = 38610432000.

The previous prime is 131574113383. The next prime is 131574113459. The reversal of 131574113440 is 44311475131.

It is a super-3 number, since 3×131574113440³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131574113396 and 131574113405.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14126385 + ... + 14135695.

It is an arithmetic number, because the mean of its divisors is an integer number (1070060544).

Almost surely, 2^131574113440 is an apocalyptic number.

131574113440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131574113440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (205451624448).

131574113440 is an abundant number, since it is smaller than the sum of its proper divisors (279329135456).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131574113440 is a wasteful number, since it uses less digits than its factorization.

131574113440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9412 (or 9404 counting only the distinct ones).

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 131574113440 its reverse (44311475131), we get a palindrome (175885588571).

The spelling of 131574113440 in words is "one hundred thirty-one billion, five hundred seventy-four million, one hundred thirteen thousand, four hundred forty".