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131579547017 is a prime number
BaseRepresentation
bin111101010001011000…
…0001000110110001001
3110120122000010112210012
41322202300020312021
54123433331001032
6140240302201305
712335443460462
oct1724260106611
9416560115705
10131579547017
1150891251196
1221601883235
13c53c1c8c39
146523197d69
1536518726b2
hex1ea2c08d89

131579547017 has 2 divisors, whose sum is σ = 131579547018. Its totient is φ = 131579547016.

The previous prime is 131579546977. The next prime is 131579547019. The reversal of 131579547017 is 710745975131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114170327881 + 17409219136 = 337891^2 + 131944^2 .

It is an emirp because it is prime and its reverse (710745975131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131579547017 - 214 = 131579530633 is a prime.

It is a super-3 number, since 3×1315795470173 (a number of 34 digits) contains 333 as substring.

Together with 131579547019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131579547019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65789773508 + 65789773509.

It is an arithmetic number, because the mean of its divisors is an integer number (65789773509).

Almost surely, 2131579547017 is an apocalyptic number.

It is an amenable number.

131579547017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131579547017 is an equidigital number, since it uses as much as digits as its factorization.

131579547017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 926100, while the sum is 50.

The spelling of 131579547017 in words is "one hundred thirty-one billion, five hundred seventy-nine million, five hundred forty-seven thousand, seventeen".