Base | Representation |
---|---|
bin | 11000100000101001… |
… | …00111110110101111 |
3 | 1020222001111102120022 |
4 | 30100110213312233 |
5 | 203422114242341 |
6 | 10013421312355 |
7 | 644041321406 |
oct | 142024476657 |
9 | 36861442508 |
10 | 13158743471 |
11 | 5642849805 |
12 | 2672a056bb |
13 | 1319242553 |
14 | 8cb88c63d |
15 | 52035be4b |
hex | 310527daf |
13158743471 has 2 divisors, whose sum is σ = 13158743472. Its totient is φ = 13158743470.
The previous prime is 13158743449. The next prime is 13158743561. The reversal of 13158743471 is 17434785131.
It is a weak prime.
It is an emirp because it is prime and its reverse (17434785131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13158743471 is a prime.
It is a super-3 number, since 3×131587434713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13158743071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6579371735 + 6579371736.
It is an arithmetic number, because the mean of its divisors is an integer number (6579371736).
Almost surely, 213158743471 is an apocalyptic number.
13158743471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13158743471 is an equidigital number, since it uses as much as digits as its factorization.
13158743471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 282240, while the sum is 44.
The spelling of 13158743471 in words is "thirteen billion, one hundred fifty-eight million, seven hundred forty-three thousand, four hundred seventy-one".
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