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13158785419921 is a prime number
BaseRepresentation
bin1011111101111100010010…
…1110110000101010010001
31201120222010101021121122001
42333133010232300222101
53211043143031414141
643553021303114001
72525455653402661
oct277370456605221
951528111247561
1013158785419921
114213678358969
121586316742901
13745b393c73ab
14336c624d21a1
1517c4546a8a31
hexbf7c4bb0a91

13158785419921 has 2 divisors, whose sum is σ = 13158785419922. Its totient is φ = 13158785419920.

The previous prime is 13158785419789. The next prime is 13158785420113. The reversal of 13158785419921 is 12991458785131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13137253966225 + 21531453696 = 3624535^2 + 146736^2 .

It is an emirp because it is prime and its reverse (12991458785131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13158785419921 - 211 = 13158785417873 is a prime.

It is a super-3 number, since 3×131587854199213 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13158785419621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6579392709960 + 6579392709961.

It is an arithmetic number, because the mean of its divisors is an integer number (6579392709961).

Almost surely, 213158785419921 is an apocalyptic number.

It is an amenable number.

13158785419921 is a deficient number, since it is larger than the sum of its proper divisors (1).

13158785419921 is an equidigital number, since it uses as much as digits as its factorization.

13158785419921 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21772800, while the sum is 64.

The spelling of 13158785419921 in words is "thirteen trillion, one hundred fifty-eight billion, seven hundred eighty-five million, four hundred nineteen thousand, nine hundred twenty-one".