Base | Representation |
---|---|
bin | 1011111101111101010010… |
… | …1110111100011100000001 |
3 | 1201120222211002111000000122 |
4 | 2333133110232330130001 |
5 | 3211044220244403432 |
6 | 43553104053430025 |
7 | 2525465423440166 |
oct | 277372456743401 |
9 | 51528732430018 |
10 | 13159053903617 |
11 | 42137a5966716 |
12 | 158639063b315 |
13 | 745b7cc0bc9b |
14 | 336c8a02006d |
15 | 17c46d03e612 |
hex | bf7d4bbc701 |
13159053903617 has 2 divisors, whose sum is σ = 13159053903618. Its totient is φ = 13159053903616.
The previous prime is 13159053903571. The next prime is 13159053903629. The reversal of 13159053903617 is 71630935095131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10838903478001 + 2320150425616 = 3292249^2 + 1523204^2 .
It is a cyclic number.
It is not a de Polignac number, because 13159053903617 - 222 = 13159049709313 is a prime.
It is not a weakly prime, because it can be changed into another prime (13159053903517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6579526951808 + 6579526951809.
It is an arithmetic number, because the mean of its divisors is an integer number (6579526951809).
Almost surely, 213159053903617 is an apocalyptic number.
It is an amenable number.
13159053903617 is a deficient number, since it is larger than the sum of its proper divisors (1).
13159053903617 is an equidigital number, since it uses as much as digits as its factorization.
13159053903617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2296350, while the sum is 53.
Adding to 13159053903617 its reverse (71630935095131), we get a palindrome (84789988998748).
The spelling of 13159053903617 in words is "thirteen trillion, one hundred fifty-nine billion, fifty-three million, nine hundred three thousand, six hundred seventeen".
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