Base | Representation |
---|---|
bin | 11000100000110110… |
… | …01001000000110011 |
3 | 1020222011201020102121 |
4 | 30100123021000303 |
5 | 203423033432042 |
6 | 10013522055111 |
7 | 644061666103 |
oct | 142033110063 |
9 | 36864636377 |
10 | 13160452147 |
11 | 5643806537 |
12 | 26734aa497 |
13 | 13196c01bb |
14 | 8cbbb5203 |
15 | 520598367 |
hex | 3106c9033 |
13160452147 has 2 divisors, whose sum is σ = 13160452148. Its totient is φ = 13160452146.
The previous prime is 13160452127. The next prime is 13160452159. The reversal of 13160452147 is 74125406131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13160452147 - 211 = 13160450099 is a prime.
It is not a weakly prime, because it can be changed into another prime (13160452127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580226073 + 6580226074.
It is an arithmetic number, because the mean of its divisors is an integer number (6580226074).
Almost surely, 213160452147 is an apocalyptic number.
13160452147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13160452147 is an equidigital number, since it uses as much as digits as its factorization.
13160452147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 13160452147 its reverse (74125406131), we get a palindrome (87285858278).
The spelling of 13160452147 in words is "thirteen billion, one hundred sixty million, four hundred fifty-two thousand, one hundred forty-seven".
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