Base | Representation |
---|---|
bin | 10011001001110110001… |
… | …101110111101111100001 |
3 | 11122211110021001122002212 |
4 | 103021312031313233201 |
5 | 133031131243342012 |
6 | 2444401314451505 |
7 | 164044510535456 |
oct | 23116615675741 |
9 | 4584407048085 |
10 | 1316243340257 |
11 | 46824106213a |
12 | 19311b293b95 |
13 | 97176400991 |
14 | 479c698182d |
15 | 24389e86b22 |
hex | 13276377be1 |
1316243340257 has 2 divisors, whose sum is σ = 1316243340258. Its totient is φ = 1316243340256.
The previous prime is 1316243340239. The next prime is 1316243340287. The reversal of 1316243340257 is 7520433426131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1178703233761 + 137540106496 = 1085681^2 + 370864^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316243340257 - 226 = 1316176231393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1316243340227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658121670128 + 658121670129.
It is an arithmetic number, because the mean of its divisors is an integer number (658121670129).
Almost surely, 21316243340257 is an apocalyptic number.
It is an amenable number.
1316243340257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316243340257 is an equidigital number, since it uses as much as digits as its factorization.
1316243340257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 41.
Adding to 1316243340257 its reverse (7520433426131), we get a palindrome (8836676766388).
The spelling of 1316243340257 in words is "one trillion, three hundred sixteen billion, two hundred forty-three million, three hundred forty thousand, two hundred fifty-seven".
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