Base | Representation |
---|---|
bin | 10011001001110110001… |
… | …101110111101111001111 |
3 | 11122211110021001122002012 |
4 | 103021312031313233033 |
5 | 133031131243341424 |
6 | 2444401314451435 |
7 | 164044510535432 |
oct | 23116615675717 |
9 | 4584407048065 |
10 | 1316243340239 |
11 | 468241062123 |
12 | 19311b293b7b |
13 | 97176400979 |
14 | 479c6981819 |
15 | 24389e86b0e |
hex | 13276377bcf |
1316243340239 has 2 divisors, whose sum is σ = 1316243340240. Its totient is φ = 1316243340238.
The previous prime is 1316243340233. The next prime is 1316243340257. The reversal of 1316243340239 is 9320433426131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1316243340239 - 212 = 1316243336143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1316243340196 and 1316243340205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316243340233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658121670119 + 658121670120.
It is an arithmetic number, because the mean of its divisors is an integer number (658121670120).
Almost surely, 21316243340239 is an apocalyptic number.
1316243340239 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316243340239 is an equidigital number, since it uses as much as digits as its factorization.
1316243340239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 41.
The spelling of 1316243340239 in words is "one trillion, three hundred sixteen billion, two hundred forty-three million, three hundred forty thousand, two hundred thirty-nine".
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