Base | Representation |
---|---|
bin | 1011111110001100011000… |
… | …1010110000101101010111 |
3 | 1201121101021101101212001121 |
4 | 2333203012022300231113 |
5 | 3211131014223122123 |
6 | 43555014032104411 |
7 | 2526001000123531 |
oct | 277430612605527 |
9 | 51541241355047 |
10 | 13163104504663 |
11 | 4215494371193 |
12 | 1587121095107 |
13 | 746377169539 |
14 | 337151d86851 |
15 | 17c60895c75d |
hex | bf8c62b0b57 |
13163104504663 has 2 divisors, whose sum is σ = 13163104504664. Its totient is φ = 13163104504662.
The previous prime is 13163104504547. The next prime is 13163104504681. The reversal of 13163104504663 is 36640540136131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13163104504663 - 213 = 13163104496471 is a prime.
It is a super-3 number, since 3×131631045046633 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13163104502663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581552252331 + 6581552252332.
It is an arithmetic number, because the mean of its divisors is an integer number (6581552252332).
Almost surely, 213163104504663 is an apocalyptic number.
13163104504663 is a deficient number, since it is larger than the sum of its proper divisors (1).
13163104504663 is an equidigital number, since it uses as much as digits as its factorization.
13163104504663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 43.
The spelling of 13163104504663 in words is "thirteen trillion, one hundred sixty-three billion, one hundred four million, five hundred four thousand, six hundred sixty-three".
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