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13163414340247 is a prime number
BaseRepresentation
bin1011111110001101100010…
…1000101100001010010111
31201121102001222102010120121
42333203120220230022113
53211132133032341442
643555104501012411
72526011451516343
oct277433050541227
951542058363517
1013163414340247
114215633253256
1215871a89b4107
137463c63cc0c2
1433718119a623
1517c625c60967
hexbf8d8a2c297

13163414340247 has 2 divisors, whose sum is σ = 13163414340248. Its totient is φ = 13163414340246.

The previous prime is 13163414340173. The next prime is 13163414340289. The reversal of 13163414340247 is 74204341436131.

It is a strong prime.

It is an emirp because it is prime and its reverse (74204341436131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13163414340247 - 223 = 13163405951639 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13163414340547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6581707170123 + 6581707170124.

It is an arithmetic number, because the mean of its divisors is an integer number (6581707170124).

Almost surely, 213163414340247 is an apocalyptic number.

13163414340247 is a deficient number, since it is larger than the sum of its proper divisors (1).

13163414340247 is an equidigital number, since it uses as much as digits as its factorization.

13163414340247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 43.

Adding to 13163414340247 its reverse (74204341436131), we get a palindrome (87367755776378).

The spelling of 13163414340247 in words is "thirteen trillion, one hundred sixty-three billion, four hundred fourteen million, three hundred forty thousand, two hundred forty-seven".