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1316551622161 is a prime number
BaseRepresentation
bin10011001010001000100…
…101110111111000010001
311122212020202010222101011
4103022020211313320101
5133032244203402121
62444452050210521
7164055243100516
oct23121045677021
94585222128334
101316551622161
1146838a082976
121931a6583a41
13971c523b2c9
1447a158ad30d
15243a707e7e1
hex13288977e11

1316551622161 has 2 divisors, whose sum is σ = 1316551622162. Its totient is φ = 1316551622160.

The previous prime is 1316551622159. The next prime is 1316551622167. The reversal of 1316551622161 is 1612261556131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1143977845761 + 172573776400 = 1069569^2 + 415420^2 .

It is a cyclic number.

It is not a de Polignac number, because 1316551622161 - 21 = 1316551622159 is a prime.

Together with 1316551622159, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1316551622167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658275811080 + 658275811081.

It is an arithmetic number, because the mean of its divisors is an integer number (658275811081).

Almost surely, 21316551622161 is an apocalyptic number.

It is an amenable number.

1316551622161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1316551622161 is an equidigital number, since it uses as much as digits as its factorization.

1316551622161 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 40.

The spelling of 1316551622161 in words is "one trillion, three hundred sixteen billion, five hundred fifty-one million, six hundred twenty-two thousand, one hundred sixty-one".