Base | Representation |
---|---|
bin | 1011111110100100010111… |
… | …1100001110001010001101 |
3 | 1201121222220002211121220001 |
4 | 2333221011330032022031 |
5 | 3211232211021102302 |
6 | 44002000554324301 |
7 | 2526316361504155 |
oct | 277510574161215 |
9 | 51558802747801 |
10 | 13169543144077 |
11 | 4218198859291 |
12 | 1588419429691 |
13 | 746b62085048 |
14 | 3375a3137765 |
15 | 17c883d3c787 |
hex | bfa45f0e28d |
13169543144077 has 2 divisors, whose sum is σ = 13169543144078. Its totient is φ = 13169543144076.
The previous prime is 13169543143993. The next prime is 13169543144141. The reversal of 13169543144077 is 77044134596131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13024548974116 + 144994169961 = 3608954^2 + 380781^2 .
It is a cyclic number.
It is not a de Polignac number, because 13169543144077 - 219 = 13169542619789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13169543144377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6584771572038 + 6584771572039.
It is an arithmetic number, because the mean of its divisors is an integer number (6584771572039).
Almost surely, 213169543144077 is an apocalyptic number.
It is an amenable number.
13169543144077 is a deficient number, since it is larger than the sum of its proper divisors (1).
13169543144077 is an equidigital number, since it uses as much as digits as its factorization.
13169543144077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7620480, while the sum is 55.
The spelling of 13169543144077 in words is "thirteen trillion, one hundred sixty-nine billion, five hundred forty-three million, one hundred forty-four thousand, seventy-seven".
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