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13170248498179 is a prime number
BaseRepresentation
bin1011111110100110111111…
…1110111011110000000011
31201122001201021002022211001
42333221233332323300003
53211240132103420204
644002154552432431
72526343015065133
oct277515776736003
951561637068731
1013170248498179
11421851aa25263
1215885956a8717
13746c4524a436
1433762caa6ac3
1517c8c5c1b4a4
hexbfa6ffbbc03

13170248498179 has 2 divisors, whose sum is σ = 13170248498180. Its totient is φ = 13170248498178.

The previous prime is 13170248498171. The next prime is 13170248498189. The reversal of 13170248498179 is 97189484207131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13170248498179 - 23 = 13170248498171 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13170248498179.

It is not a weakly prime, because it can be changed into another prime (13170248498171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6585124249089 + 6585124249090.

It is an arithmetic number, because the mean of its divisors is an integer number (6585124249090).

Almost surely, 213170248498179 is an apocalyptic number.

13170248498179 is a deficient number, since it is larger than the sum of its proper divisors (1).

13170248498179 is an equidigital number, since it uses as much as digits as its factorization.

13170248498179 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24385536, while the sum is 64.

The spelling of 13170248498179 in words is "thirteen trillion, one hundred seventy billion, two hundred forty-eight million, four hundred ninety-eight thousand, one hundred seventy-nine".