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1317123299543 is a prime number
BaseRepresentation
bin10011001010101010101…
…010101001100011010111
311122220201120212012022112
4103022222222221203113
5133034432031041133
62445024511221235
7164105354215442
oct23125252514327
94586646765275
101317123299543
11468652846617
12193325b1781b
13972867cb54c
1447a6b7a2659
15243dc355648
hex132aaaa98d7

1317123299543 has 2 divisors, whose sum is σ = 1317123299544. Its totient is φ = 1317123299542.

The previous prime is 1317123299497. The next prime is 1317123299551. The reversal of 1317123299543 is 3459923217131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3459923217131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1317123299543 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1317123299491 and 1317123299500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1317123299573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658561649771 + 658561649772.

It is an arithmetic number, because the mean of its divisors is an integer number (658561649772).

Almost surely, 21317123299543 is an apocalyptic number.

1317123299543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1317123299543 is an equidigital number, since it uses as much as digits as its factorization.

1317123299543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1224720, while the sum is 50.

The spelling of 1317123299543 in words is "one trillion, three hundred seventeen billion, one hundred twenty-three million, two hundred ninety-nine thousand, five hundred forty-three".