Base | Representation |
---|---|
bin | 111101010101011001… |
… | …1001010000001011001 |
3 | 110120222102011201021122 |
4 | 1322222303022001121 |
5 | 4124222411242433 |
6 | 140301524015025 |
7 | 12342003152606 |
oct | 1725263120131 |
9 | 416872151248 |
10 | 131714555993 |
11 | 50950484459 |
12 | 2163ab31475 |
13 | c5611795c7 |
14 | 653709d6ad |
15 | 365d640198 |
hex | 1eaacca059 |
131714555993 has 2 divisors, whose sum is σ = 131714555994. Its totient is φ = 131714555992.
The previous prime is 131714555981. The next prime is 131714556011. The reversal of 131714555993 is 399555417131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113674842649 + 18039713344 = 337157^2 + 134312^2 .
It is a cyclic number.
It is not a de Polignac number, because 131714555993 - 212 = 131714551897 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (131714555593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65857277996 + 65857277997.
It is an arithmetic number, because the mean of its divisors is an integer number (65857277997).
Almost surely, 2131714555993 is an apocalyptic number.
It is an amenable number.
131714555993 is a deficient number, since it is larger than the sum of its proper divisors (1).
131714555993 is an equidigital number, since it uses as much as digits as its factorization.
131714555993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2551500, while the sum is 53.
The spelling of 131714555993 in words is "one hundred thirty-one billion, seven hundred fourteen million, five hundred fifty-five thousand, nine hundred ninety-three".
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