13171904747 has 2 divisors, whose sum is σ = 13171904748. Its totient is φ = 13171904746.

The previous prime is 13171904741. The next prime is 13171904749. The reversal of 13171904747 is 74740917131.

It is a strong prime.

It is an emirp because it is prime and its reverse (74740917131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13171904747 - 2²⁶ = 13104795883 is a prime.

It is a super-2 number, since 2×13171904747² (a number of 21 digits) contains 22 as substring.

Together with 13171904749, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13171904698 and 13171904707.

It is not a weakly prime, because it can be changed into another prime (13171904741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6585952373 + 6585952374.

It is an arithmetic number, because the mean of its divisors is an integer number (6585952374).

Almost surely, 2^13171904747 is an apocalyptic number.

13171904747 is a deficient number, since it is larger than the sum of its proper divisors (1).

13171904747 is an equidigital number, since it uses as much as digits as its factorization.

13171904747 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 148176, while the sum is 44.

The spelling of 13171904747 in words is "thirteen billion, one hundred seventy-one million, nine hundred four thousand, seven hundred forty-seven".