Base | Representation |
---|---|
bin | 1011111110101111010010… |
… | …1001111100111011111011 |
3 | 1201122021110101110012211101 |
4 | 2333223310221330323323 |
5 | 3211304211414231424 |
6 | 44003203504512231 |
7 | 2526452123500561 |
oct | 277536451747373 |
9 | 51567411405741 |
10 | 13172474367739 |
11 | 4219462413a85 |
12 | 1588ab701b677 |
13 | 74720b438a0b |
14 | 3377a0559a31 |
15 | 17c9a6348344 |
hex | bfaf4a7cefb |
13172474367739 has 2 divisors, whose sum is σ = 13172474367740. Its totient is φ = 13172474367738.
The previous prime is 13172474367709. The next prime is 13172474367763. The reversal of 13172474367739 is 93776347427131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13172474367739 - 213 = 13172474359547 is a prime.
It is not a weakly prime, because it can be changed into another prime (13172474367709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6586237183869 + 6586237183870.
It is an arithmetic number, because the mean of its divisors is an integer number (6586237183870).
Almost surely, 213172474367739 is an apocalyptic number.
13172474367739 is a deficient number, since it is larger than the sum of its proper divisors (1).
13172474367739 is an equidigital number, since it uses as much as digits as its factorization.
13172474367739 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 112021056, while the sum is 64.
The spelling of 13172474367739 in words is "thirteen trillion, one hundred seventy-two billion, four hundred seventy-four million, three hundred sixty-seven thousand, seven hundred thirty-nine".
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