Base | Representation |
---|---|
bin | 11000100010010111… |
… | …00011011001100111 |
3 | 1021000001121000012111 |
4 | 30101023203121213 |
5 | 203434311040033 |
6 | 10015054101451 |
7 | 644304604066 |
oct | 142113433147 |
9 | 37001530174 |
10 | 13173143143 |
11 | 564a994466 |
12 | 26777aa887 |
13 | 131c214874 |
14 | 8cd75a1dd |
15 | 5217537cd |
hex | 3112e3667 |
13173143143 has 2 divisors, whose sum is σ = 13173143144. Its totient is φ = 13173143142.
The previous prime is 13173143089. The next prime is 13173143161. The reversal of 13173143143 is 34134137131.
13173143143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13173143143 - 221 = 13171045991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13173143173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6586571571 + 6586571572.
It is an arithmetic number, because the mean of its divisors is an integer number (6586571572).
Almost surely, 213173143143 is an apocalyptic number.
13173143143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13173143143 is an equidigital number, since it uses as much as digits as its factorization.
13173143143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9072, while the sum is 31.
The spelling of 13173143143 in words is "thirteen billion, one hundred seventy-three million, one hundred forty-three thousand, one hundred forty-three".
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