Base | Representation |
---|---|
bin | 10011001010111111110… |
… | …110001000101110101111 |
3 | 11122221122100110222022111 |
4 | 103022333312020232233 |
5 | 133041144012213432 |
6 | 2445124043224451 |
7 | 164120230413262 |
oct | 23127766105657 |
9 | 4587570428274 |
10 | 1317478632367 |
11 | 468815383407 |
12 | 193404b18127 |
13 | 97312300b61 |
14 | 47aa2a5acd9 |
15 | 2440d644347 |
hex | 132bfd88baf |
1317478632367 has 2 divisors, whose sum is σ = 1317478632368. Its totient is φ = 1317478632366.
The previous prime is 1317478632287. The next prime is 1317478632443. The reversal of 1317478632367 is 7632368747131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1317478632367 - 211 = 1317478630319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1317478635367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658739316183 + 658739316184.
It is an arithmetic number, because the mean of its divisors is an integer number (658739316184).
Almost surely, 21317478632367 is an apocalyptic number.
1317478632367 is a deficient number, since it is larger than the sum of its proper divisors (1).
1317478632367 is an equidigital number, since it uses as much as digits as its factorization.
1317478632367 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21337344, while the sum is 58.
The spelling of 1317478632367 in words is "one trillion, three hundred seventeen billion, four hundred seventy-eight million, six hundred thirty-two thousand, three hundred sixty-seven".
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