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1317796885241 is a prime number
BaseRepresentation
bin10011001011010010110…
…100001011001011111001
311122222110112022220011222
4103023102310023023321
5133042322000311431
62445215412401425
7164131143464234
oct23132264131371
94588415286158
101317796885241
11468968a94511
12193493616275
139736321ca75
1447ad302241b
152442b55b57b
hex132d2d0b2f9

1317796885241 has 2 divisors, whose sum is σ = 1317796885242. Its totient is φ = 1317796885240.

The previous prime is 1317796885217. The next prime is 1317796885243. The reversal of 1317796885241 is 1425886977131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 972188112016 + 345608773225 = 985996^2 + 587885^2 .

It is a cyclic number.

It is not a de Polignac number, because 1317796885241 - 26 = 1317796885177 is a prime.

It is a super-3 number, since 3×13177968852413 (a number of 37 digits) contains 333 as substring.

It is a Sophie Germain prime.

Together with 1317796885243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1317796885243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658898442620 + 658898442621.

It is an arithmetic number, because the mean of its divisors is an integer number (658898442621).

Almost surely, 21317796885241 is an apocalyptic number.

It is an amenable number.

1317796885241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1317796885241 is an equidigital number, since it uses as much as digits as its factorization.

1317796885241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20321280, while the sum is 62.

The spelling of 1317796885241 in words is "one trillion, three hundred seventeen billion, seven hundred ninety-six million, eight hundred eighty-five thousand, two hundred forty-one".