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1317805273949 is a prime number
BaseRepresentation
bin10011001011010011010…
…100001011001101011101
311122222111010010002022212
4103023103110023031131
5133042331122231244
62445220312250205
7164131305003143
oct23132324131535
94588433102285
101317805273949
114689727a402a
121934963a0965
1397364b990b8
1447ad41a7593
152442c166d9e
hex132d350b35d

1317805273949 has 2 divisors, whose sum is σ = 1317805273950. Its totient is φ = 1317805273948.

The previous prime is 1317805273921. The next prime is 1317805273973. The reversal of 1317805273949 is 9493725087131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1317805273849 + 100 = 1147957^2 + 10^2 .

It is an emirp because it is prime and its reverse (9493725087131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1317805273949 - 212 = 1317805269853 is a prime.

It is a super-2 number, since 2×13178052739492 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1317805273999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658902636974 + 658902636975.

It is an arithmetic number, because the mean of its divisors is an integer number (658902636975).

Almost surely, 21317805273949 is an apocalyptic number.

It is an amenable number.

1317805273949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1317805273949 is an equidigital number, since it uses as much as digits as its factorization.

1317805273949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11430720, while the sum is 59.

The spelling of 1317805273949 in words is "one trillion, three hundred seventeen billion, eight hundred five million, two hundred seventy-three thousand, nine hundred forty-nine".