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13179468317 is a prime number
BaseRepresentation
bin11000100011000111…
…01011101000011101
31021000111111100201012
430101203223220131
5203442420441232
610015441425005
7644412426611
oct142143535035
937014440635
1013179468317
115653514684
12267993b165
13132061a882
148d0525341
155220a29b2
hex3118eba1d

13179468317 has 2 divisors, whose sum is σ = 13179468318. Its totient is φ = 13179468316.

The previous prime is 13179468301. The next prime is 13179468343. The reversal of 13179468317 is 71386497131.

13179468317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10647969721 + 2531498596 = 103189^2 + 50314^2 .

It is an emirp because it is prime and its reverse (71386497131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13179468317 - 24 = 13179468301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13179468377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6589734158 + 6589734159.

It is an arithmetic number, because the mean of its divisors is an integer number (6589734159).

Almost surely, 213179468317 is an apocalyptic number.

It is an amenable number.

13179468317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13179468317 is an equidigital number, since it uses as much as digits as its factorization.

13179468317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 762048, while the sum is 50.

The spelling of 13179468317 in words is "thirteen billion, one hundred seventy-nine million, four hundred sixty-eight thousand, three hundred seventeen".