Search a number
-
+
131799132137 is a prime number
BaseRepresentation
bin111101010111111010…
…1110010011111101001
3110121012022022121221102
41322233311302133221
54124411034212022
6140314144451145
712344051065361
oct1725765623751
9417168277842
10131799132137
11509941a07a2
1221663319ab5
13c57584c86a
1465443d79a1
153665c99a92
hex1eafd727e9

131799132137 has 2 divisors, whose sum is σ = 131799132138. Its totient is φ = 131799132136.

The previous prime is 131799132109. The next prime is 131799132191. The reversal of 131799132137 is 731231997131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128143236841 + 3655895296 = 357971^2 + 60464^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131799132137 is a prime.

It is a super-2 number, since 2×1317991321372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131799132091 and 131799132100.

It is not a weakly prime, because it can be changed into another prime (131799132337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65899566068 + 65899566069.

It is an arithmetic number, because the mean of its divisors is an integer number (65899566069).

Almost surely, 2131799132137 is an apocalyptic number.

It is an amenable number.

131799132137 is a deficient number, since it is larger than the sum of its proper divisors (1).

131799132137 is an equidigital number, since it uses as much as digits as its factorization.

131799132137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 214326, while the sum is 47.

The spelling of 131799132137 in words is "one hundred thirty-one billion, seven hundred ninety-nine million, one hundred thirty-two thousand, one hundred thirty-seven".