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13179962897 is a prime number
BaseRepresentation
bin11000100011001011…
…00100011000010001
31021000112102111010222
430101211210120101
5203443032303042
610015500202425
7644416556543
oct142145443021
937015374128
1013179962897
115653822222
122679b39415
131320761a1a
148d0613693
1552214e2d2
hex311964611

13179962897 has 2 divisors, whose sum is σ = 13179962898. Its totient is φ = 13179962896.

The previous prime is 13179962893. The next prime is 13179962899. The reversal of 13179962897 is 79826997131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11949987856 + 1229975041 = 109316^2 + 35071^2 .

It is a cyclic number.

It is not a de Polignac number, because 13179962897 - 22 = 13179962893 is a prime.

It is a super-2 number, since 2×131799628972 (a number of 21 digits) contains 22 as substring.

Together with 13179962899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13179962893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6589981448 + 6589981449.

It is an arithmetic number, because the mean of its divisors is an integer number (6589981449).

Almost surely, 213179962897 is an apocalyptic number.

It is an amenable number.

13179962897 is a deficient number, since it is larger than the sum of its proper divisors (1).

13179962897 is an equidigital number, since it uses as much as digits as its factorization.

13179962897 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10287648, while the sum is 62.

The spelling of 13179962897 in words is "thirteen billion, one hundred seventy-nine million, nine hundred sixty-two thousand, eight hundred ninety-seven".