Base | Representation |
---|---|
bin | 111101011010101110… |
… | …1010111111010111101 |
3 | 110121102212200200110111 |
4 | 1322311131113322331 |
5 | 4130104202121013 |
6 | 140331353110021 |
7 | 12346304234533 |
oct | 1726535277275 |
9 | 417385620414 |
10 | 131893395133 |
11 | 50a324239a5 |
12 | 2168a9b8311 |
13 | c58c234c96 |
14 | 6552b34153 |
15 | 366e1b973d |
hex | 1eb5757ebd |
131893395133 has 2 divisors, whose sum is σ = 131893395134. Its totient is φ = 131893395132.
The previous prime is 131893395121. The next prime is 131893395169. The reversal of 131893395133 is 331593398131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96409008004 + 35484387129 = 310498^2 + 188373^2 .
It is an emirp because it is prime and its reverse (331593398131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131893395133 - 213 = 131893386941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131893390133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65946697566 + 65946697567.
It is an arithmetic number, because the mean of its divisors is an integer number (65946697567).
Almost surely, 2131893395133 is an apocalyptic number.
It is an amenable number.
131893395133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131893395133 is an equidigital number, since it uses as much as digits as its factorization.
131893395133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 787320, while the sum is 49.
The spelling of 131893395133 in words is "one hundred thirty-one billion, eight hundred ninety-three million, three hundred ninety-five thousand, one hundred thirty-three".
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