Base | Representation |
---|---|
bin | 1100000000000011001110… |
… | …1110000110001001001111 |
3 | 1201201102121202001111100211 |
4 | 3000000303232012021033 |
5 | 3212141333324130434 |
6 | 44021411434503251 |
7 | 2531210403046024 |
oct | 300006356061117 |
9 | 51642552044324 |
10 | 13195007255119 |
11 | 4227a75669858 |
12 | 1591345294b27 |
13 | 74938c7b9081 |
14 | 3388dadb354b |
15 | 17d374639464 |
hex | c0033b8624f |
13195007255119 has 2 divisors, whose sum is σ = 13195007255120. Its totient is φ = 13195007255118.
The previous prime is 13195007255071. The next prime is 13195007255123. The reversal of 13195007255119 is 91155270059131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13195007255119 - 29 = 13195007254607 is a prime.
It is a super-2 number, since 2×131950072551192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13195007255219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6597503627559 + 6597503627560.
It is an arithmetic number, because the mean of its divisors is an integer number (6597503627560).
Almost surely, 213195007255119 is an apocalyptic number.
13195007255119 is a deficient number, since it is larger than the sum of its proper divisors (1).
13195007255119 is an equidigital number, since it uses as much as digits as its factorization.
13195007255119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 425250, while the sum is 49.
The spelling of 13195007255119 in words is "thirteen trillion, one hundred ninety-five billion, seven million, two hundred fifty-five thousand, one hundred nineteen".
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