Base | Representation |
---|---|
bin | 111101011100101100… |
… | …0100011011100100001 |
3 | 110121121110120222022002 |
4 | 1322321120203130201 |
5 | 4130223031143411 |
6 | 140342104253345 |
7 | 12351034015505 |
oct | 1727130433441 |
9 | 417543528262 |
10 | 131959240481 |
11 | 50a66607542 |
12 | 216a8a71255 |
13 | c59ca7a723 |
14 | 655b794305 |
15 | 3674d7433b |
hex | 1eb9623721 |
131959240481 has 2 divisors, whose sum is σ = 131959240482. Its totient is φ = 131959240480.
The previous prime is 131959240447. The next prime is 131959240487. The reversal of 131959240481 is 184042959131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83082874081 + 48876366400 = 288241^2 + 221080^2 .
It is a cyclic number.
It is not a de Polignac number, because 131959240481 - 210 = 131959239457 is a prime.
It is a super-2 number, since 2×1319592404812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131959240487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65979620240 + 65979620241.
It is an arithmetic number, because the mean of its divisors is an integer number (65979620241).
Almost surely, 2131959240481 is an apocalyptic number.
It is an amenable number.
131959240481 is a deficient number, since it is larger than the sum of its proper divisors (1).
131959240481 is an equidigital number, since it uses as much as digits as its factorization.
131959240481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 47.
The spelling of 131959240481 in words is "one hundred thirty-one billion, nine hundred fifty-nine million, two hundred forty thousand, four hundred eighty-one".
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