Base | Representation |
---|---|
bin | 11110000000010000101001… |
… | …000101000110100000111111 |
3 | 122022020011221000122112101011 |
4 | 132000100221011012200333 |
5 | 114244010033141434232 |
6 | 1144353125453500051 |
7 | 36536512405315534 |
oct | 3600205105064077 |
9 | 568204830575334 |
10 | 131959264405567 |
11 | 39056678649a95 |
12 | 1297270a7a1627 |
13 | 5882922544411 |
14 | 2482c108bcd8b |
15 | 103c86b1da547 |
hex | 78042914683f |
131959264405567 has 2 divisors, whose sum is σ = 131959264405568. Its totient is φ = 131959264405566.
The previous prime is 131959264405547. The next prime is 131959264405583. The reversal of 131959264405567 is 765504462959131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131959264405567 - 239 = 131409508591679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131959264405537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65979632202783 + 65979632202784.
It is an arithmetic number, because the mean of its divisors is an integer number (65979632202784).
Almost surely, 2131959264405567 is an apocalyptic number.
131959264405567 is a deficient number, since it is larger than the sum of its proper divisors (1).
131959264405567 is an equidigital number, since it uses as much as digits as its factorization.
131959264405567 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 244944000, while the sum is 67.
The spelling of 131959264405567 in words is "one hundred thirty-one trillion, nine hundred fifty-nine billion, two hundred sixty-four million, four hundred five thousand, five hundred sixty-seven".
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