Base | Representation |
---|---|
bin | 1100000000001000110110… |
… | …1111000011000010011111 |
3 | 1201201120111222202112202002 |
4 | 3000002031233003002133 |
5 | 3212202431432011413 |
6 | 44022221343352515 |
7 | 2531263001402123 |
oct | 300021557030237 |
9 | 51646458675662 |
10 | 13196517453983 |
11 | 4228680085596 |
12 | 15916a6bb273b |
13 | 74957063c576 |
14 | 338a017ad583 |
15 | 17d411eea958 |
hex | c008dbc309f |
13196517453983 has 2 divisors, whose sum is σ = 13196517453984. Its totient is φ = 13196517453982.
The previous prime is 13196517453887. The next prime is 13196517454007. The reversal of 13196517453983 is 38935471569131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13196517453983 - 212 = 13196517449887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13196517453283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6598258726991 + 6598258726992.
It is an arithmetic number, because the mean of its divisors is an integer number (6598258726992).
Almost surely, 213196517453983 is an apocalyptic number.
13196517453983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13196517453983 is an equidigital number, since it uses as much as digits as its factorization.
13196517453983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 73483200, while the sum is 65.
The spelling of 13196517453983 in words is "thirteen trillion, one hundred ninety-six billion, five hundred seventeen million, four hundred fifty-three thousand, nine hundred eighty-three".
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